![\left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right]=\left[\begin{array}{ccc}0.5&-3\\0&1\\\end{array}\right]\left[\begin{array}{ccc}2\\-3\\\end{array}\right]](/tpl/images/0415/0308/8430a.png)
we get![A^{-1}AX=A^{-1}B\\ \\We\ know\\A^{-1}A = I\ and\ IX = X\\\\\therefore X = A^{-1}B\\\\\therefore \left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right]=\left[\begin{array}{ccc}0.5&-3\\0&1\\\end{array}\right]\left[\begin{array}{ccc}2\\-3\\\end{array}\right]](/tpl/images/0415/0308/6c106.png)
![A^{-1}=\left[\begin{array}{ccc}0.5&-3\\0&1\end{array}\right]\\\\X=\left[\begin{array}{ccc}x_{1}\\ x_{2}\end{array}\right] \\\\B=\left[\begin{array}{ccc}2\\-3\end{array}\right]](/tpl/images/0415/0308/c6455.png)
Which equation can be used to solve
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