•you roll two standard number cubes.
what is the probability of rolling a 3 on
one cube, but not both cubes?

5/18

Step-by-step explanation:

There are two ways this can happen: you roll a 3 on the first cube and not a 3 on the second cube, or you roll not a 3 on the first cube and 3 on the second cube.

P = (1/6)(5/6) + (5/6)(1/6)

P = 5/36 + 5/36

P = 10/36

P = 5/18

the answer is su.k.my? ? co.kc

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: