Suppose that the new england colonials baseball team is equally likely to win a game as not to win it. if 4 colonials games are chosen at random, what is the probability that exactly 3 of those games are won by the colonials? round your response to at least three decimal places.

The answer is 0.25

Step-by-step explanation:

This is a binomial distribution question, since it is equally likely probability of success (p) is 0.5 and the probability of failure (q) is 0.5.

Using binomial distribution formula

P(x) = n CX PX qn-x where C means combination

X =3 , n= 4

P(x) = 4c3 × (0.5) raise to power 3 ×(0.5) raise to power 1

P(x) = 4× 1/8 × 1/2

P(x)= 0.25

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

greater than one

step-by-step explanation: