Suppose we want to estimate the average weight of an adult male in dekalb county, georgia. we draw a random sample of 1,000 men from the population and weigh them. we find that the average man in our sample weighs 190 pounds, and the standard deviation of the sample is 30 pounds. what is the 95% confidence interval?

(188.1384, 191.8616 )

Step-by-step explanation:

When population standard deviation is not known, then the  confidence interval for population mean is given by :-

                  (1)

, where n= sample size.

= sample mean

t* = critical value.

s = sample standard deviation.

As per given , we have

n= 1000

Degree of freedom : df = n-1=999

s= 30

Significance level :

Using t-distribution table , the critical value =

The 95% confidence interval will be :

Hence, the required confidence interval = (188.1384, 191.8616 )

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?