On a coordinate plane, two parabolas open up. the solid-line parabola goes through (1, 3), has a vertex at (3, negative 1), and goes through (5, 3). the dashed-line parabola goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). which best describes the transformation from the graph of f(x) = x2 to the graph of f(x) = (x – 3)2 – 1? left 3 units, down 1 unit left 3 units, up 1 unit right 3 units, down 1 unit right 3 units, up 1 unit

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

replace   with   27   and simplify.

10 , 27 , 10 , 70 , 10 , 35 , 10 , 48

step-by-step explanation:

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step-by-step explanation: