Write an equation in standard form for the line that passes
through (-1,-2) and (3.0)

y+2=1/2(x+1)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-2))/(3-(-1))

m=(0+2)/(3+1)

m=2/4

m=1/2

y-y1=m(x-x1)

y-(-2)=1/2(x-(-1))

y+2=1/2(x+1)

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.