Given: cp is perpendicular to ab, cp bisects ab, prove: ca=cb

Proved   CA=CB

Step-by-step explanation:

Given,

In ΔABC,  CP is perpendicular to AB.

And CP bisects AB.

So,  AP=PB   and   ∠CPA=∠CPB=90°

The figure of the triangle is in the attachment.

Now, In ΔACP and ΔBCP.

AP = PB(given)

∠CPA = ∠CPB = 90°(perpendicular)

CP = CP(common)

So, By Side-Angle-Side congruence property;

     ΔACP ≅ ΔBCP

According to the property of congruence;

"If two triangles are congruent to each other then their corresponding sides are also equal."

Therefore,  CA = CB (corresponding side of congruent triangle)

CA = CB  Hence Proved

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

i’m here for points.