16. financial literacy a specific car's fuel economy in miles per gallon can be

approximated by f(x) = 0.56x4 - 0.18x3 - 0.016x2 + 1.38x - 0.38,

where x represents the car's speed in miles per hour. determine the fuel economy

when the car is traveling 40, 50, and 60 miles per hour.

a) 29.50 miles per gallon    b) 29.87 miles per gallon     c) 28.19 miles per gallon

Step-by-step explanation:

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056x^4 - 0.000018x^3 - 0.016x^2 + 1.38x - 0.38

where x represents the car speed in miles per hour.

when x = 40 miles per hour

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(40)^4 - 0.000018(40)^3 - 0.016(40)^2 + 1.38(40) - 0.38 = 1.4336 - 1.152 - 25.6 + 55.2 - 0.38 = 29.50 miles per gallon

Similarly,

when x = 50

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(50)^4 - 0.000018(50)^3 - 0.016(50)^2 + 1.38(50) - 0.38 = 3.5 - 2.25 - 40 + 69 - 0.38 = 29.87 miles per gallon

Similarly,

when x = 60

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(60)^4 - 0.000018(60)^3 - 0.016(60)^2 + 1.38(60) - 0.38 = 7.26 - 3.89 - 57.6 + 82.8 - 0.38 = 28.19 miles per gallon

answer: t=3

step-by-step explanation:

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