An old-fashioned chinese restaurant offers a family dinner where you get to choose one dish from “column a” (which has 8 dishes), one dish from “column b” (which has 10 dishes) and one dish from “column c” (which has 5 dishes). how many different family dinners can be chosen?

There are 400 ways to choose the dinner.

Step-by-step explanation:

Since we have to choose one dish from each column and we have three columns A ,B and C .

Number of choices for Column A = 8

Number of choices for column B = 10

Number of choices for column C = 5 dishes

Number of different family dinners can be chosen = 8x10 x5

                                                                                     = 400 ways

                                                [Using fundamental principle of Multiplication]

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.