Minh has a coin collection of dimes and nickels worth $1.70. the number of nickels is four more than the number of dimes. how many of each coin does she have ?

The number of coins each she have are 10 dimes coin and 14 nickel coins.

Step-by-step explanation:

Given:

Minh has a coin collection of dimes and nickels worth $1.70.

The number of nickels is four more than the number of dimes.

Now, to find each coins she have.

Let the number of dimes be .

And the number of nickels be .

As the value of dimes = $0.10, and the value of nickel = $0.05.

Now, according to question:

⇒

⇒

Subtracting both sides by 0.20 we get:

⇒

Dividing both sides by 0.15 we get:

⇒.

Number of dimes = 10.

Number of nickel =

Therefore, the number of coins each she have are 10 dimes coin and 14 nickel coins.