Agarage is drawn using a scale of 2 2/3 inch =6feet if the actual height is 68 ft what is the height of the garage

Step-by-step explanation:

The drawing of the garage is a smaller representation of the actual garage. A garage is drawn using a scale of 2 2/3 inch = 6feet. Let us first convert 2 2/3 inch to improper fraction. It becomes 8/3 inch.

Let us determine the unit measurement.

If 6feet = 8/3 inch,

1 foot will be 8/3 ÷ 6 = 8/3×1/6

= 8/18 inches. Therefore

if the actual height is 68 ft , then, the height of the garage on the drawing will be

68 × 8/18 = 272/9 = 30 2/9 inches

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

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step-by-step explanation: