Abaseball is thrown in a parabolic arc. it's position above the ground at a given point in time can be represented by the quadratic function latex: p\left(t\right)=\frac{1}{2}gt^2+v_0 t+p_0 p ( t ) = 1 2 g t 2 + v 0 t + p 0 , where latex: t\ge0 t ≥ 0 , latex: g g is -32 ft/sec/sec, latex: v_0 v 0 is initial velocity, and latex: p_0 p 0 is its initial position above the ground. if the ball was thrown straight up at 16 ft/sec when it was 5 ft above the ground, how high did it go? (type the number, do not include units in your answer)