Abag contains 4 white, 2 blue, and 6 red marbles. a marble is drawn from the bag, replaced, and another marble is drawn. find the following
probabilities:
enter your answers a simplified fractions, with / representing the fraction bar
1. both marbles are red
2. both marbles are blue
3. the first marble is red and the second is blue
other is red

Step-by-step explanation:

Total marble = 6+4+2 = 12

n(W) = 4

n(B) = 2

n(R) = 6

P(W) = 4/12 = 1/3

P(B) = 2/12 = 1/6

P(R) = 6/12 = 1/2

1. P(R and R) = 1/2 × 1/2 = 1/4

2. P(B and B) = 1/6 × 1/6 = 1/36

3. P(R and (B or R) = 1/6 × (1/6+1/2)

= 1/6 × (2/3)

= 1/9

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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