Given: △abc, ab=5 sqrt2 m∠a=45°, m∠c=30° find: bc and ac
pls
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The measure of side BC = 5 unit and The measure of side AC = 5 unit

Step-by-step explanation:

Given as :

In a triangle ΔABC

The measure of side = AB = 5 unit

The measure of angle A = ∠A = 45°

The measure of angle C = ∠C = 30°

Now, For a triangle the sum of three angles of triangle = 180°

∴, ∠A + ∠B + ∠C = 180°

Or, 45° + ∠B +30° = 180°

Or , ∠B =  180° - ( 45° +  30°)

Or,  ∠B =  180° - 75°

i.e  ∠B =  105°

Now, From figure

Sin 45°  =

Or, =

Or, BC =

∴ BC = 5

So, The measure of side BC = 5 unit

Again , from figure

Cos 45°  =

Or, =

Or, AC =

∴  AC = 5

So, The measure of side AC = 5 unit

Hence The measure of side BC = 5 unit and The measure of side AC = 5 unit  Answer

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step-by-step explanation: