Arandom sample of individuals participating in a survey in 2000 was asked ""do you favor or oppose the death penalty for murder? "" the results were 130 out of 200 females favored capital punishment and 188 out of 250 males favored capital punishment. find an approximate 95% confidence interval for the difference between the proportion of females and males that favor capital punishment. based upon your confidence interval do you believe the proportion of males that favor capital punishment is greater than the proportion of females that favor capital punishment? justify your answer.

At 5% significance level, the two proportions are equal.

Step-by-step explanation:

Given that a  random sample of individuals participating in a survey in 2000 was asked ""Do you favor or oppose the death penalty for murder?""

Label:  

                     Females      Males                Total

N                 200                 250               450

X                      130                188                318                  

p                       0.7222           0.752            0.7067

(left tailed test)

p difference = -0.0298

Standard error for difference =

Z statistic =

p value = 0.0828

Since p >0.05, we accept H0

At 5% significance level, the two proportions are equal.

its electric no smoke

step-by-step explanation:

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.