An adult ticket to a museum costs 3$ more than a children’s ticket. when 200 adult tickets and 100 children tickets are sold, the total revenue is $2100. what is the cost of children’s ticket?

The cost of children’s ticket is $ 5

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

Cost of one adult ticket = 3 + cost of one children ticket

a = 3 + c  ------ eqn 1

Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

Thus the cost of children’s ticket is $ 5

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

5050 i think

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