Given: line cg bisects ∠abd, line cg bisects ∠efh, ∠1 ↔ ∠4
prove: ∠5 ↔ ∠6
statement reason 1. line cg bisects ∠abd line cg bisects ∠efh ∠1 ↔ ∠4 1. 2. ∠1 ↔ ∠2 2. 3. ∠2 ↔ ∠4 3. 4. ∠2, ∠5 form a linear pair ∠4, ∠6 form a linear pair 4. 5. ∠2, ∠5 are supplementary angles ∠4, ∠6 are supplementary angles 5. 6. ∠5 ↔ ∠6 6. what is the reason for statement 3?