Find the sum of the first 9 terms in the following
geometric series.
do not round your answer.
64 + 32 + 16 +

127 3/4

Step-by-step explanation:

you are just dividing the previous term by 2.

4th: 16 / 2 = 8

5th: 8 / 2 = 4

6th: 4 / 2 = 2

7th: 2 / 2 = 1

8th: 1 / 2 = 1/2

9th: 1/2 / 2 = 1/4

Add in groups of three to make it easier.

64 + 32 + 16 = 112

8 + 4 + 2 = 14

1 + 1/2 + 1/4 = 3/2 + 1/4 = 1 3/4

112 + 14 + 7/4 = 127 3/4

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

what statement? is there an image?