Dorle the destroyer gets paid by space command to vapors aliens. last week she blasted 6 borgons and 23 kirkins and was paid $700. this week she blasted 6 borgons and 18 kirkins and was paid $600 wright a system of equations that models the situation and calculate how much she gets paid for each borgon and kirkin

For each borgon and kirkin, she is paid $20 and $40 respectively.

Step-by-step explanation:

let x = price of a borgon.

y = price of a kirkin.

Equations

for last week,

6x + 23y = 700 *

For this week,

6x + 18y = 600 **

solving the two equations simultaneously using the elimination method, subtract eqn ** from eqn *

You would be left with

5y = 100.

y = 100/5

y = 20.

put y = 20 into any of the equations.

So putting it into equation...* ,

6x + 23 (20) = 700

6x + 460 = 700

6x = 700-460

6x = 240

x = 240/6

x = 40.

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."