An airplane takes 4 hours to travel a distance of 2800 miles with the wind. the return trip takes 5 hours against the wind. find the speed of the plane in still air and the speed of the
wind

Speed of airplane in still air = 630 mile per hour

Speed of wind = 70 miles per hour.

Step-by-step explanation:

Let speed of plane in still air = miles/hour

Let speed of wind = miles/hour

Speed of airplane with the wind can be given by = miles/hour

Speed of airplane against the wind can be given by = miles/hour

Distance of the trip = 2800 miles

Time taken by airplane to travel with the wind = 4 hours

Speed of plane with wind =

Distance of the return trip (same trip distance) = 2800 miles

Time taken by airplane to travel with the wind = 5 hours

Speed of plane with wind =

So, we have the system of equations:

A)

B)

Using elimination method to solve.

Adding equation A to B to eliminate .

+

We get

Dividing both sides by 2.

∴

Using in equation A to find

Subtracting both sides by 630

∴

Speed of airplane in still air = 630 mile per hour

Speed of wind = 70 miles per hour.

answer: 1 and 3

step-by-step explanation:

there is no question content here, but you for the free points! : d