Find the point b on ac such that the ratio of ab to bc is 3: 1

and

Step-by-step explanation:

Let us assume that the coordinates of a and c are respectively and  , and the coordinates of point b are  .

So, we have to express the coordinates of b in terms of the coordinates of a and c provided the ratio of segment ab to bc is 3 : 1.

Now, we know, the formula of coordinate geometry that if there are two known points P   and Q   and the point R divides PQ line segment in m : n ratio internally, then the coordinates of R will be given by .

Therefore, using this formula we can write  

and  

(Answer)

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)