Isaac’s television is 25 inches wide and 18 inches high. what is the diagonal size of isaac’s television? round to the nearest tenth if necessary.

Step-by-step explanation:

The television takes the shape of a rectangle whose width is 25 inches and whose height is 18 inches. To determine the length of the diagonal, we will apply Pythagoras theorem. It states that

Hypotenuse^2 = opposite^2 + adjacent^2

From the given information,

Adjacent side = 25 inches

Opposite side = 18 inches

Diagonal = hypotenuse.

Therefore

Diagonal^2 = 25^2 + 18^2

Diagonal^2 = 625 + 324 = 949

Take square roots of both sides of the equation, it becomes

Diagonal = √949 = 30.805 inches

Approximately 30.8 inches to the nearest tenth.

a

step-by-step explanation:

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: