Darnel’s retirement party cost $33, plus an additional $1 for each guest he invites. what is the maximum number of guests there can be if darnel can afford to spend a total of $42 on his retirement party?

20

Step-by-step explanation:

He's going to need a very sharp pencil to cross out the people he cannot afford to invite but would like to.

Equation

y = 33 + 1x

y = 42

42 = 33  + x

Solution

42 = 22 + x               Subtract 22 from both sides.

42 - 22 = 22 -22 + x    

20 = x

This means that if each extra person costs $1.00 then he can invite 20 more people (20 * 1 = 20)

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: