Through: (2,5), perp. to y =- 2/3x +3

Find the equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3

The equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3 in slope intercept form is

Given that line passes through (2, 5) and perpendicular to line having equation

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form y = mx + c and given equation of line we get

Thus slope of given line is

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

Slope of given line x slope of line perpendicular to it = -1

Let us find equation of line with slope and passes through (2, 5)

Substitute and (x, y) = (2, 5)

Thus the required equation of line is:

Substitute and c = 2 in eqn 1

Thus the equation of line perpendicular to given line is found out

the answer is 24

step-by-step explanation: