1) after a dilation, (-60, 15) is the image of (-12, 3). what are the coordinates of the image of (-2,-7) after the same dilation?
a) k = 5; (-10, -35)
b) k = 5; (-7, -2)
c) k = 1/5; (-2/5,-7/5)
d) k = 1/5; (-5/2,-5/7)

a) k = 5; (-10, -35)

Step-by-step explanation:

Given:

Co-ordinates:

Pre-Image = (-12,3)

After dilation

Image = (-60,15)

The dilation about the origin can be given as :

Pre-Image

where represents the scalar factor.

We can find value of for the given co-ordinates by finding the ratio of or co-ordinates of the image and pre-image.

For the given co-ordinates.

Pre-Image = (-12,3)

Image = (-60,15)

The value of

or

As we get for both ratios i.e of and   co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.

To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.

Pre-Image Image

Pre-Image Image (Answer)

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50