An artist is hired to create an art display for the interior of a city building. the display is to span a total width of 10 yd . the artist decides to cover this space with equally sized portraits placed side-by-side in a horizontal line with no gaps. each portrait has a width of 45 in . how many portraits will be used in the display

8 portraits are going to be used in the display.

Step-by-step explanation:

This problem can be solved as a rule of three problem.

Each yd has 36 inches.

The display is to span a total width of 10 yd. So it is a total width of 360 inches.

Each portrait has a width of 45 in. How many portraits can there be?

1 portrait - 45 in

x portraits - 360 in

8 portraits are going to be used in the display.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

well what did you do it matters what you did : )

step-by-step explanation: