Last week, 108 cars received parking violations in the main university parking lot. of these, 27 had unpaid parking tickets from a previous violation. assuming that last week was a random sample of all parking violators, find the 95 percent confidence interval for the percentage of parking violations that have prior unpaid parking tickets.

95 percent confidence interval

[0.208,0.29166]

Step-by-step explanation:

First we identificate the sample proportion p = 27 /108, and we find the 95 percent confidence interval for P(population proportion) in this context the parking violations that have prior unpaid parking tickets.

Then α = 0.05 and 1 - α/2 = 0.975

Thus

The 95 percent confidence interval is

[ p ± 1.96 ]

[0.25  ± 1.96 ]

[0.208,0.29166]

where is the rest of the

step-by-step explanation:

srry idk

step-by-step explanation: