Ateam plays 120 matches a year. in its first year the team wins 45% of its matches. the 2nd year ,the team wins 55 % . how many more matches did they win in the second year.

they win 12 more matches in the second year

Step-by-step explanation:

Each year, the team plays a total of 120 matches. In its first year the team wins 45% of its matches. This means that the total number of matches that the team won in the first year is

45/100/× 120 = 54

The 2nd year ,the team wins 55% out of 120 matches. This means that the total number of matches that the team won in the second year is

55/100/× 120 = 66

Number of matches for the second year - number of matches for the first leg is 66 - 54 = 12

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

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