Arecent study by ohio state university reported at science daily suggests that students with cell phones may take more risks than students that do not have cell phones. in a sample of 305 ohio state university female students, 128 (42%) responded that if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.

use the above survey results to test the hypotheses
h0: p = 0.50
ha: p < 0.50
where p is the proportion of female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.

question 1. what is the value of the test statistic z for this hypothesis test? (use 2 decimal places in your answer).

The value of the test statistic z for this hypothesis test is -2.79

Step-by-step explanation:

Consider the provided information.

To calculate the test statistic use the formula:

Where, z  is Test statistics, n is Sample size, p₀ = Null hypothesized value  and = Observed proportion.

p₀ = 0.50

Thus 1-p₀= 0.50

42% responded that if they had a cell phone, thus

The sample size is 305.

Substitute the respective values in the above formula.

Hence, the value of the test statistic z for this hypothesis test is -2.79

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

apex answer is: true.