what are the zeros of the polynomial function
f(x) = x^3-5x^2-6x

a. x= -2, x=0 and x=3
b. x=-1, x=0 and x=6
c. x=-3, x=0 and x=2
d. x=-6, x=0 and x=1

Option B

The zeros of the polynomial function are x = 0 , x = 6, x = -1

Solution:

Given function is:

To find: zeros of the polynomial function

To find the zeros of polynomial function, set the function equal to zero and then solve for x.

Taking "x" as common term, we get

Equating to zero,

So one of the zeros of polynomial is x = 0

Let us solve to find other zeros

Let us solve using quadratic formula,

Using the above formula,

Substituting the values of a, b, c in above formula,

Thus the zeros of the polynomial function are x = 0 , x = 6, x = -1

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )