Acollection of 33 coins having dimes quarters and nickels, there are 3 times more nickels then dimes and half the amount of dimes as nickels, all of the coins equal $3.30 how many of each coin?

Each coins are quarters of 6, nickels of 18 and the dimes of 9.

Step-by-step explanation:

There is a mistake in question.

The question must be:

A collection of 33 coins having dimes quarters and nickels, there are 3 times as many nickels as quarters, and one-half as many dimes as nickels, all of the coins equal $3.30 how many coins of each kind are there?

Now, to find the number coins of each.

Let the quarters be .

Nickels be .

And the dimes be .

So, the total collection of coins are:

On adding the fractions we get:

Multiplying both sides by 2 we get:

Dividing both sides by 11 we get:

Thus, quarters = 6.

Nickels =

Dimes =

Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.

16.9 times 2.85

step-by-step explanation:

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches