What is the distance between the y-intercept and the x-intercept of the line whose equation is y=3x+12

The distance between the y-intercept and the x-intercept of the line is 12.64911 units or units

Solution:

Given equation is y = 3x + 12

We have to find the distance between y-intercept and the x-intercept of the line whose equation is y = 3x + 12

Let us first find the x - intercept and y - intercept

The x-intercept is the point at which the line crosses the x-axis. At this point, the y-coordinate is zero.

The y-intercept is the point at which the line crosses the y-axis. At this point, the x-coordinate is zero

Finding x - intercept:

To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'.

Substitute y = 0 in given equation

y = 3x + 12

0 = 3x + 12

3x = -12

x = -4

Thus the x - intercept is (-4, 0)

Finding y - intercept:

To find the y-intercept, plug 0 in for 'x' and solve for 'y'

Substitute x = 0 in given equation

y = 3x + 12

y = 3(0) + 12

y = 12

Thus the y - intercept is (0, 12)

Now let us find the distance between x intercept and y intercept

Distance between two points is given by:

Here the distance between (-4, 0) and (0, 12) is given as:

Thus the distance between the y-intercept and the x-intercept of the line is 12.64911 units or units

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

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