Eight times a number plus five times another number is -13 the sum of the two numbers is 1 what are these numbers

The two numbers are -6 and 7

Solution:

Given that eight times a number plus five times another number is -13

The sum of two numbers is 1

To find: the two numbers

Let the two numbers be "a" and "b"

From given information,

Eight times a number plus five times another number = -13

eight times a number "a" + five times another number "b" = -13

8a + 5b = -13 eqn 1

Also given that sum of two numbers is 1

sum of two numbers = 1

a + b = 1 eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "b"

From eqn 2,

a = 1 - b eqn 3

Substitute eqn 3 in eqn 1

8(1 - b) + 5b = -13

8 - 8b + 5b = -13

8 - 3b = -13

-3b = -13 - 8

-3b = -21

Substitute b = 7 in eqn 3

a = 1 - 7

Thus the two numbers are -6 and 7

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

answer: 5

step-by-step explanation: