An isosceles triangle is shaped in such a way that its longer sides are 4 cm less than triple
its shortest side. if the entire triangle's perimeter is 41 cm, what are each of its side lengths?

the length of each of the longest sides is 17 inches.

The length of the shortest side is 7 inches

Step-by-step explanation:

Let x represent the length of one of the longest side of the isosceles triangle.

Let y represent the length of one of the longest side of the isosceles triangle.

In an isosceles triangle, 2 sides have equal length. Therefore, the the length if the two longest sides is 2x.

The isosceles triangle is shaped in such a way that its longer sides are 4 cm less than triple its shortest side. This means that the

x = 3y - 4

The formula for the perimeter of a triangle is the sum of the length of each side. If the entire triangle's perimeter is 41 cm, it means that

2x + y = 41 - - - - - - - - - - 1

Substituting x = 3y - 4 into equation 1, it becomes

2(3y - 4) + y = 41

6y - 8 + y = 41

6y + y = 41 + 8

7y = 49

y = 49/7 = 7

Substituting y = 7 into x = 3y - 4, it becomes

x = 3×7 - 4 = 17

20

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !