Which are real zeroes of this function? x3 + 2x2 – 9x – 18.
a. 1, 2, 3
b. 3, -3, 2
c. 2, 3, -6
d. 1, -1, 18
e. -2, 3, -3

The real zeros of function are (-2, 3, -3)

Given function is:

To find the zeroes of the function, we just need to evaluate the values and check if the function/expression tends to 0.

Let

On grouping the terms we get,

Taking as common term from first two terms and "9" as common term from last two terms,

Taking (x + 2) as common term,

We know that,

Applying the above identity,

We equate the function to 0 , to find the zeros of polynomial function

(x + 3)(x - 3)(x + 2) = 0

Therefore zeros are:

x + 3 = 0

x - 3 = 0

x + 2 = 0

Thus zeros are (-2, 3, -3) Option E is correct

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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sine

step-by-step explanation: