Write the equation of a line that is perpendicular to the given line and that passes through the given point. y= 2/3x + 9 ; (–6, 5)

y = - x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x + 9 ← is in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - , thus

y = - x + c ← is the partial equation

To find c substitute (- 6, 5) into the partial equation

5 = 9 + c ⇒ c = 5 - 9 = - 4

y = - x - 4 ← equation of perpendicular line

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.