The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 . a dotplot shows that it is reasonable to assume that the population is approximately normal. you wish to test whether the mean tuition and fees for private colleges is different from . compute the value of the test statistic and state the number of degrees of freedom.

The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.

Step-by-step explanation:

Consider the provided information.

The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .

Thus, n = 12, σ = 5000

degrees of freedom = n-1 = 12-1 = 11

Formula to find the value of z is:

Where is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.

Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.

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step-by-step explanation:

step-by-step explanation:

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