What is the distance, in feet, across the patch of swamp water?

Therefore the distance across the patch of swamp water is 50 ft

Step-by-step explanation:

Given:

VW = 100 ft

WX = 60 ft

XZ = 30 ft

To Find:

ZY = l = ?

Solution:

In  Δ VWX and Δ YZX

∠W ≅ ∠ Z    …………..{measure of each angle is 90° given}

∠VXW ≅ ∠YXZ      ..............{vertically opposite angles  are equal}

Δ ABC ~ Δ DEC ….{Angle-Angle Similarity test}

If two triangles are similar then their sides are in proportion.

On substituting the given values we get

Therefore the distance across the patch of swamp water is 50 ft

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

table 3 represents a direct variation function. : )