Given: ln⊥km, kl≅ml prove: δkln≅δmln

The Proof is given below.

Step-by-step explanation:

Given:

LN⊥KM,

KL≅ML

To Prove:

ΔKLN≅ΔMLN

Proof:

In  Δ KLN and Δ MLN

KL ≅ ML     ……….{Given i.e Hypotenuse }

LN ≅ LN     …………..{Reflexive Property}

∠ LNK ≅ ∠ LNM  ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}

Δ KLN ≅ Δ MLN     ….{By Hypotenuse Leg Theorem} Proved

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

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