Formulate but do not solve the following exercise as a linear programming problem. kane manufacturing has a division that produces two models of fireplace grates, x units of model a and y units of model b. to produce each model a requires 3 lb of cast iron and 8 min of labor. to produce each model b grate requires 5 lb of cast iron and 3 min of labor. the profit for each model a grate is $2.00, and the profit for each model b grate is $1.50. if 800 lb of cast iron and 1200 min of labor are available for the production of grates per day, how many grates of each model should the division produce per day to maximize kane's profits p in dollars?

maximize p = subject to the constraints
cast iron =
labor =
model a =
y = 0

z  - 2*x   -  1.5*y   =  0   maximize

subject to:

3*x  +  5*y   ≤  800

8*x  + 3*y   ≤   1200  

x, y  >  0

Step-by-step explanation:

Formulation:

Kane Manufacturing produce  x  units of model A (fireplace grates)

and  y units of model B

                  quantity   Iron cast lbs    labor (min)   Profit $    

Model  A          x               3                      8                  2

Model  B          y               5                      3                  1.50

We have   800 lbs of iron cast  and 1200 min  of labor available

We need to find out how many units  x  and units y per day to maximiza profit

First constraint   Iron cast lbs     800 lbs

3*x  +  5*y   ≤  800             3*x  +  5*y  +  s₁   =  800

Second constraint  labor    1200 min available

8*x  + 3*y   ≤   1200              8*x  + 3*y           + s₂  =  1200  

Objective function

z  =  2*x  +  1.5*y         to maximize    z  - 2*x   -  1.5*y   =  0  

x > 0   y  >  0

The first table is  ( to apply simplex method )

z         x        y       s₁      s₂       Cte

1        -2       -1.5     0      0          0

0        3         5       1       0        800

0        8         3       0       1       1200

(23*2)-12=x     x=34

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph