The polynomial function f(x)=−x^3−2x^2+5x−6 has one negative zero.

between what integers does this negative zero occur?

−6 and −5

−5 and −4

−4 and −3

−3 and −2

  -4 and -3

Step-by-step explanation:

You can evaluate the function at the middle of the range of interest, which is [-6, -2], and see which side of that the root lies on.

  f(-4) = ((-(-4) -2)(-4) +5)(-4) -6 = (2(-4) +5)(-4) -6 = (-3)(-4) -6 = 6

Since f(0) = -6, the root lies between -4 and 0. The x-value of -3 further divides the interval [-4, -2] in half, so we can try ...

  f(-3) = ((-(-3) -2)(-3) +5)(-3) -6 = (1(-3) +5)(-3) -6 = 2(-3) -6 = -12

The interval [-4, -3] brackets the root.

_____

We have written the polynomial in "Horner form" to make evaluation easier.

  f(x) = ((-x -2)x +5)x -6

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: