Abag contains one red one yellow one blue and one green marble what is the probability of choosing a green marble not replacing it and then choosing a red marble

The total probability of choosing a green marble not replacing it and then choosing a red marble is

Solution:

Given that bag contains one red one yellow one blue and one green marble

To find: Probability of choosing a green marble not replacing it and then choosing a red marble

The probability of an event is given as:

Here total number of possible outcomes = 1 red + 1 yellow + 1 blue + 1 green

total number of possible outcomes = 4 marbles

Here favourable outcome is choosing a green marble not replacing it and then choosing a red marble

Let us first find probability of choosing a green marble

Favorable outcome = green marble

Number of favorable outcomes = 1

Now without replacing, we have to choose a red marble

Without replacing means, green marble is not considered

So total number of possible outcomes = 4 - 1 = 3

The total probability of choosing a green marble not replacing it and then choosing a red marble:

So the required probability is

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.