Equation if the line that is parallel to 3x+y=10 and passes through (-2,4)

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

m = slope

The equation of the given line is

3x+y=10

y = - 3x + c

Comparing it with the slope intercept equation, slope, m = -3

If a line is parallel to another line, the slope of the line is the same with the slope of the given line. This means that the slope of the line passing through the point (-2,4) is -3

We would determine the intercept, c by substituting m = -3, x = -2 and y = 4 into y = mx + c. It becomes

4 = -3 × -2 + c

4 = 6 + c

c = 4 - 6 = - 2

The equation becomes

y = - 3x + - 2

answ5

step-by-step explanation:

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answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.