Let y = safe load in pounds and x = depth in inches for a certain type of rectangular horizontal beam. a constant of
proportionality exists such that y = kx^2.
determine the constant k for a beam with y = 1,000 pounds and x = 5 inches.
what is a safe load if the depth of the beam is 10 inches?
800 pounds
4,000 pounds
10,000 pounds

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

happy to

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step-by-step explanation: