Find point p that divides segment ab into a 2: 3 ratio. the point should be closer to a. a(-3,1) and b(3,5)

First, work out how much you need to add to A's x and y coordinates in order to get to point B from point A.

So (using Ax to mean x-coordinate of A, Ay the y-coordinate of A, etc):
x-difference = Bx - Ax = 3 - (-3) = 3 + 3 = 6
y-difference = By - Ay = 5 - 1 = 4

Now, if the point divides the segment AB in the ratio 2:3, then it is 2/(2+3) of the way along the line AB.

i.e. it is 2/5 of the way along the line AB.

We therefore need to add 2/5 of the x- and y-differences to point A to get point p:
px = Ax + (2/5)*(x-difference) = -3 + (2/5)*6 = -3 + 12/5 = -15/5 + 12/5 = -3/5 = -0.6
py = Ay + (2/5)*(y-difference) = 1 + (2/5)*4 = 1 + 8/5 = 5/5 + 8/5 = 13/5 = 2.6

Therefore coordinates of p are (-0.6, 2.6)

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for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for