Nour and rana are shopping for a christmas tree. they are deciding between 2 different types of trees (real and fake) and 4 colors for the ornaments (white, silver, gold, and purple). they each created a display to represent the sample space of randomly picking a type of tree and a color for the ornaments.

There are no actual questions provided for this post. However, based on the details given, the question will probably asked about the following:

a) list the sample space

b) the probability of having a type of tree with certain color

I will explain to you how to answer such questions. Though it may defer a bit from the actual question, you could use guidance to provide the basis for your answer.

Answer and Step-by-step explanation:

List of sample space must incorporate each sample on two different events given that both events are independent to each other.

In this case we have two events:

i) type of tree - real or fake

ii) color of ornaments - white (W), silver (S), gold (G) or purple (P)

Each sample must have one choices of each events. In this case the sample space are:

(real,W), (real,S), (real,G),(real,P)

(fake,W), (fake,S), (fake,G), (fake,P)

To find probability of any choices, we need to know the probability of each samples. Assuming the selection is random and both events are independent to each other, we can have each sample for each event having different probability.

Event: type of tree

Number of choice: 2

Hence, Pr(real) = Pr(fake) = 1/2

Event: ornament color

Number of choices: 4

Hence, Pr(W) = Pr(S) = Pr(G) = Pr(P) = 1/4

To find the probability of any sample space, we can base our probability using individual probability as above.

For example, if the choice is fake tree with red ornaments

Pr(fake & R) = Pr(fake) x Pr(R)

= 1/2 x 1/4

= 1/8

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.