Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park. max's family spent $146 on 3 adults tickets and 2 youth tickets. what is the price of a youth ticket?

The price of 1 youth ticket is $ 22

Solution:

Let "y" be the price of 1 youth ticket

Let "a" be the price of 1 adult ticket

To find: price of 1 youth ticket

Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park

So we can frame a equation as:

2 adult tickets x price of 1 adult ticket + 3 youth tickets x price of 1 youth ticket = 134

2a + 3y = 134 ---- eqn 1

Max's family spent $146 on 3 adults tickets and 2 youth tickets

So we can frame a equation as:

3 adult tickets x price of 1 adult ticket + 2 youth tickets x price of 1 youth ticket = 146

3a + 2y = 146 ----- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "y"

Multiply eqn 1 by 3

6a + 9y = 402 ---- eqn 3

Multiply eqn 2 by 2

6a + 4y = 292 ----- eqn 4

Subtract eqn 4 from eqn 3

6a + 9y = 402

6a + 4y = 292

( - ) -------------------

5y = 110

y = 22

Thus the price of 1 youth ticket is $ 22

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2