George invested a total of $5,000 at the beginning of the year in two different funds. at the end of the year, his investment had grown to $5,531. the money in the first fund earned 9%, while the money in the second fund earned 13.5%. write a system of equations, then solve it to find out how much of the $5,000 was invested into each fund at the beginning of the year

The amount invested at 9% was $3,200 and the amount invested at 13.5% was $1,800

Step-by-step explanation:

Let

x ----> the amount invested at 9% (first fund)

5,000-x ----> the amount invested at 13.5% (second fund)

Remember that

The total interest earned is equal to

we know that

The amount earned by the first fund at 9% plus the amount earned by the second fund at 13.5% must be equal to $531

so

the linear equation that represent this situation is equal to

solve for x

so

therefore

The amount invested at 9% was $3,200 and the amount invested at 13.5% was $1,800