In the regular octagon, the numeric value of the area of the shaded region is twice more than the numeric value of the length of ab. find the area of the unshaded region.

A =  (2+√8)L² - 2L, where L is the length of AB

Step-by-step explanation:

Lets call L the length of one side. The octagon can be divided in 8 triangles composed by the vertices of the octagon and the center. The base of each triangle has length L and the height is L/2 + M, with M such that 2M² = L². This is because the center of the octagon is located at middle height of the center sides. You can reach that height by 'travelling' from the bottom side throught one slanted side (which is the hypotenuse of a isosceles rectangle triangle of height M) and then you travel throught a center side half its length. Thus, h = L/2 + L/√2.

The area of each triangle of the octagon therefore is, as a result, h*L/2 = L²/4 + L²/2√2

Hence, the area of the octagon is 8*(L²/4 + L²/2√2) = (2+√8)L². The unshaded region area can be computed by taking this number and substract to it the value of 2L, which is the area of the shaded region (The double of the length of a side)

As a result,

A =  (2+√8)L² - 2L

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

c. side angle side. u shares the same sides