(-+30i) express your answer in the form (a+bi)

-14 - 30 i

Step-by-step explanation:

We recall that when combining complex numbers, we need to combine the real parts among themselves to get the new real part, and the imaginary parts among themselves to get the imaginary part of the new complex that results from the operation.

In our case the firs complex number is "-8" which consists of strictly real part (with zero imaginary part). The second complex number is (6+30 i) which has real part = 6 and imaginary part = 30 i.

now we operate separately on the real parts and on the imaginary parts performing the requested subtraction:

Real part:  -8 - 6 = -14

Imaginary part: 0 i - 30 i = -30 i

Therefore the final complex number that results from this subtraction is: "-14 - 30 i"

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

you save $70

discount would be 35% off

step-by-step explanation: